202207071711 Solution to 1976-CE-AMATH-I-XX

Find the ratio in which the line segment joining the points P(-2,3) and Q(3,5) is divided by the y-axis. Find also the y-coordinate of the point of division.


Preparation.

i. Set up a Cartesian coordinate system on a grid-lined graph paper:

ii. Plot the origin O(0,0), point P(-2,3), and point Q(3,5):

iii. Join all three points with segments OP, OQ, and PQ:

iv. Target at the y-intercept of line segment PQ:

v. By the built-in function Properties... of The Geometer’s Sketchpad,

we are half done with y\textrm{-intercept}=3.8.

vi. Next, what is the ratio PE:EQ?

1^\circ:

2^\circ:

 

Numerically,

\begin{aligned} PE:EQ & = \frac{PE}{EQ} \\ & = \frac{2.15}{3.23} \\ & = 0.666\qquad \textrm{(3 s.f.)} \\ \end{aligned}

for

Analytically,

for points P(-2,3) and Q(3,5) on the Cartesian plane with origin O(0,0), write vectors \mathbf{OP}=-2\,\hat{\mathbf{i}}+3\,\hat{\mathbf{j}} and \mathbf{OQ}=3\,\hat{\mathbf{i}}+5\,\hat{\mathbf{j}}, so that

\begin{aligned} \mathbf{PQ} & =\mathbf{PO}+\mathbf{OQ} \\ & = -\mathbf{OP}+\mathbf{OQ} \\ & = -\Big( -2\,\hat{\mathbf{i}}+3\,\hat{\mathbf{j}}\Big) + \Big( 3\,\hat{\mathbf{i}}+5\,\hat{\mathbf{j}} \Big) \\ & =5\,\hat{\mathbf{i}}+2\,\hat{\mathbf{j}} \\ \end{aligned}

the magnitude m being

\begin{aligned} m(PQ) & = |\mathbf{PQ}| \\ & = |(5,2)| \\ & = \sqrt{ (5)^2 + (2)^2 } \\ & = \sqrt{29}\enspace \textrm{units} \\ \end{aligned}

and the slope s

s(PQ) = \displaystyle{\frac{2}{5}}.

The segment \mathbf{PQ} is t-parametrized as such

\mathbf{PQ}(t)=(-2+t)\,\hat{\mathbf{i}} + \displaystyle{\bigg( 3+\frac{2}{5}t\bigg) }\,\hat{\mathbf{j}}

where t\in [0,5].

\because \enspace \triangle PSR\cong \triangle PQT

\therefore\enspace \displaystyle{\frac{PS}{PQ} =\frac{PR}{PT}=\frac{2}{5}}

\therefore\enspace PS:SQ = PS:(PQ-PS)=2:(5-2)=2:3