201902182224 Electric circuit diagrams (Elementary) Q4

The blogger claims no originality of his question below.

Circuit0004

Find the equivalent resistance, in terms of R_1, R_2, R_3, and R_4, when the switch is

i. open;

ii. closed.


Solution.

i. When the switch is open, we draw the following diagram:Circuit0004Sol001The equivalent resistance of R_1 and R_3 in series is their sum R_1+R_3. Similarly, that of R_2 and R_4 in series is R_2+R_4. The equivalent resistance R_{\mathrm{eq}} of R_1+R_3 and R_2+R_4 in parallel is given by \displaystyle{\frac{1}{R_{\mathrm{eq}}}=\frac{1}{R_1+R_3}+\frac{1}{R_2+R_4}}. Thus R_{\mathrm{eq}}=\displaystyle{\frac{(R_1+R_3)(R_2+R_4)}{R_1+R_2+R_3+R_4}}.

ii. When the switch is closed, we draw the following diagram:Circuit0004Sol002The equivalent resistance of R_1 and R_2 in parallel is \displaystyle{\frac{R_1R_2}{R_1+R_2}}. Similarly, that of R_3 and R_4 in parallel is \displaystyle{\frac{R_3R_4}{R_3+R_4}}. Thus the equivalent resistance of them in series is R_{\mathrm{eq}}=\displaystyle{\frac{R_1R_2}{R_1+R_2}+\frac{R_3R_4}{R_3+R_4}}.

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