202105251532 Homework 2 (Q1)

Prove that the electric field is always perpendicular to equipotential surface.


Solution.

(The solution below is based on the manuscript of 2016-2017 PHYS3450 Electromagnetism Homework 2 Solution.)

\mathbf{E} is the electric field vector; \mathbf{dr} is a line element vector on the equipotential surface.

For any two arbitrary points a and b on the equipotential surface, we have the same potential there (i.e., V(a)=V(b)). From -\int_a^b\mathbf{E}\cdot\mathbf{dr}=V(b)-V(a)=0. Thus \mathbf{E}\cdot \mathbf{dr}=0, or, \mathbf{E}\perp\mathbf{dr}.

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