202004231606 Exercise 1, Section 1.1

Determine whether the vectors emanating from the origin and terminating at the following pair of points are parallel.

(a) (3,1,2) and (6,4,2)

(b) (-3,1,7) and (9,-3,-21)

(c) (5,-6,7) and (-5,6,-7)

(d) (2,0,-5) and (5,0,-2)


Background.

Two nonzero vectors x and y are called parallel if y=tx for some nonzero real number t. (Thus nonzero vectors having the same or opposite directions are parallel.)

Text on pg.3


Solution.

(a) Let x=(3,1,2) and y=(6,4,2). Apparently \nexists\, t\in \mathbb{R} such that y=tx. For otherwise (6,4,2)=t(3,1,2), the system of equations

\begin{aligned} 6 & = 3t \\ 4 & = 1t \\ 2 & = 2t \\ \end{aligned}

is inconsistent. They are not parallel.

(b) Let x=(-3,1,7) and y=(9,-3,-21), then y=-3x. The vectors x and y are in opposite direction and the magnitude of y is three times that of x. They are parallel.

(c) Let x=(5,-6,7) and y=(-5,6,-7). Observe that they are in equal magnitude but in opposite direction, i.e., y=-x. They are also parallel.

(d) Let x=(2,0,-5) and y=(5,0,-2). Assume t\in\mathbb{R} s.t. y=tx, i.e.,

\begin{aligned} 5 & = 2t \\ 0 & = 0t \\ -2 & = 5t \\ \end{aligned}

no way will the first and the third lines agree. They are nonparallel.

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