201902190246 Electric circuit diagrams (Elementary) Q5

The blogger claims no originality of his problem below.

Circuit0012

Find the equivalent resistance of the circuit above.


Solution.

In series, 5\,\mathrm{\Omega} +9\,\mathrm{\Omega} +1\,\mathrm{\Omega} =15\,\mathrm{\Omega}.

Circuit0012Sol001

In parallel, \bigg(\displaystyle{\frac{1}{10\,\mathrm{\Omega} }+\frac{1}{15\,\mathrm{\Omega} }}\bigg)^{-1}=6\,\mathrm{\Omega}.

Circuit0012Sol002

In series, 4\,\mathrm{\Omega} +6\,\mathrm{\Omega} +2\,\mathrm{\Omega} =12\,\mathrm{\Omega}.

Circuit0012Sol003

In parallel, \bigg(\displaystyle{\frac{1}{4\,\mathrm{\Omega} }+\frac{1}{12\,\mathrm{\Omega} }}\bigg)^{-1}=3\,\mathrm{\Omega}.

Circuit0012Sol004

Finally, the equivalent resistance of the resistors above in series is R_{\mathrm{eq}}=3\,\mathrm{\Omega} +3\,\mathrm{\Omega} +4\,\mathrm{\Omega} =10\,\mathrm{\Omega}.

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